Изменения

<tex dpi="350">Cycle(A)(t)=\sum_{k=0}^{\infty}Cycle_k(BA)(t)=0+\sum_{k=1}^{\infty}\frac{BA(t)^k}{k}=-ln\left (1-A(t) \right )=ln\left (\frac{1}{1-A(t)}\right )</tex>