Изменения

<tex>2^na_{2^n} = 2^n \frac1{2^{np}} = \left(\frac1{2^{p - 1}}\right)^n</tex>.

<tex>\sum\limits_{k n = 1}^\infty 2^n a_{2^n} =</tex> <tex>\sum\limits_{k n = 1}^\infty \left(\frac1{2^{p-1}}\right)^n =</tex> <tex>\sum\limits_{k n = 1}^\infty q^n</tex>